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A binary symmetric channel (BSC) has a transition probability of 1/8. If the binary transmit symbol *X *is such that P(*X*=0) = 9/10, then the probability of error for an optimum receiver will be

*X*is such that P(

*X*=0) = 9/10, then the probability of error for an optimum receiver will be

(A) 7/80 | (B) 63/80 | (C) 9/10 | (D) 1/10 |

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